Given a list of daily temperatures T
, return a list such that, for each day in the input, tells you how many days you would have to wait until a warmer temperature. If there is no future day for which this is possible, put 0
instead.
For example, given the list of temperatures T = [73, 74, 75, 71, 69, 72, 76, 73]
, your output should be [1, 1, 4, 2, 1, 1, 0, 0]
.
Note: The length of temperatures
will be in the range [1, 30000]
. Each temperature will be an integer in the range [30, 100]
.
Solution:
Iterate backwards and maintain a stack, pop until stack top is more than current element.
class Solution {
public:
vector<int> dailyTemperatures(vector<int>& T) {
stack<pair<int,int>> s;
vector<int> ans(T.size());
for(int i = T.size()-1; i>=0; i--){
while(!s.empty() && s.top().first <= T[i]){
s.pop();
}
if(s.empty()) ans[i] = 0;
else ans[i]=s.top().second-i;
s.push(make_pair(T[i],i));
}
return ans;
}
};