Return the number of permutations of 1 to `n`

so that prime numbers are at prime indices (1-indexed.)

*(Recall that an integer is prime if and only if it is greater than 1, and cannot be written as a product of two positive integers both smaller than it.)*

Since the answer may be large, return the answer **modulo 10^9 + 7**.

**Example 1:**

```
Input: n = 5
Output: 12
Explanation: For example [1,2,5,4,3] is a valid permutation, but [5,2,3,4,1] is not because the prime number 5 is at index 1.
```

**Example 2:**

```
Input: n = 100
Output: 682289015
```

**Constraints:**

`1 <= n <= 100`

**Solution:**

Count the number of primes <= n, call it m, and return m!*(n-m)!.

```
class Solution {
public:
int numPrimeArrangements(int n) {
int M = 1e9+7;
vector<int> p{2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97};
vector<int> is_p(101, 0);
for(int i : p){
is_p[i] = 1;
}
int a=0,b=0;
for(int i=1;i<=n;i++){
if(is_p[i]) a++;
else b++;
}
long long ans = 1;
for(int i=1;i<=a;i++){
ans = (ans * i) % M;
ans %= M;
}
for(int i=1;i<=b;i++){
ans = (ans * i) % M;
ans %= M;
}
return ans;
}
};
```